Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

My weakest point in calculus has always been solving actual integrals. Of course I understand how everything works, and can apply things. The problem keeps that I waste a lot of time on, as discovered later, dead ends...

I have a lot of trouble deciding if I see a random function how I would start. Should I try to use the integration by parts rule? The substitution rule (good substition)? Convert the function first to a different function? Especially when things become non trivial and a combination is required I more often than not first try the wrong method.

Is this problem just a lack of experience and something that can only be solved by exercising more problems. Or are there tricks/standard approaches (ie: first try substitution then ... ) I can follow?

An very simple example of a solution I simply couldn't see is (though this is just an example):

$$\int {\frac{1}{x^2+6x+13}}dx$$

share|improve this question
    
For rational functions, there is a standard procedure: sosmath.com/calculus/integration/rational/rational.html In this particular example, write $x^2+6x+13=(x+3)^2+4$. –  wj32 Jun 15 '13 at 8:56
    
Well most functions I meet aren't rational to be frank - this was just an example I had to solve before posting the question. Mostly functions have some kind of sine/exponential growth within them. But thanks anyways, good to know at least a subset can be solved :). –  paul23 Jun 15 '13 at 9:03

1 Answer 1

up vote 2 down vote accepted

Part is obviously experience which allows you to more easily recognise what kinds of integrals you're dealing with but a large part is simply understanding the different methods of integration and why they work. This should make it easier for you to "diagnose" problems.

e.g. Integration by substitution often works well when an integral has a similar form to one that you already know (for instance your example and $\int \frac{1}{x^2+1} \mathrm{d}x=\arctan(x)$). Integration by parts often works well when you can identify two multiplying functions, one of which isn't too costly to integrate and the other which differentiates to zero eventually or in some cases to the same type of function. etc.

Of course throughout this process you also need to keep a keen eye out for any simplifications or other changes you might be able to make e.g. trigonometric identities, indices, etc.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.