I'm a beginner to maths and have trouble simplyfying the following function:
$$\frac{p^y \cdot (pq)^o}{p^{2y+o} \cdot q^{o-2}}$$
The final answer is
$$p^{-y} \cdot q^2$$
But I'm not sure how to get there.
Any help is appreciated.
|
I'm a beginner to maths and have trouble simplyfying the following function: $$\frac{p^y \cdot (pq)^o}{p^{2y+o} \cdot q^{o-2}}$$ The final answer is $$p^{-y} \cdot q^2$$ But I'm not sure how to get there. Any help is appreciated. |
||||
|
|
|
Here's the method in general, without actually working out your example. You should do that yourself to seal the concepts. The intermediate goal is to get all the powers of p and q separated in both the numerator and denominator. In this case, it's almost there, with the exception of (pq)^o. So expand that first, using the principle (x*y)^a = x^a * y^a. Then gather the p's and q's using the properties of multiplication and exponentiation, x^a * x^b = x^(a+b). Finally, match the p's in the numerator and denominator, likewise the q's, and using the principle x^a / x^b = x^(a-b) calculate the ultimate powers of p and q. Note that there are two ways you could handle the power of p in the final answer, since it is negative. |
|||||||||||
|