# Find area of triangle ABC

BD Perpendicular AC , AB =BC=a

Find the area of triangle ABC

I have tried Googling , I used formula 1/2 (base X Height) . Used Pythagorean theorem. Anyone can suggest me solution.

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perhaps i should say something more helpful, pythagoras theorem. – Lost1 May 18 '13 at 2:46
Thanks , i will workout ! – SSK May 18 '13 at 2:46
@Lost1, please let's be civil. – vadim123 May 18 '13 at 2:51

Let $y$ represent the distance $CD$. Then $y^2+x^2=a^2$, or $y=\sqrt{a^2-x^2}$. Now you have enough to find the area of triangle $BCD$ using your area formula. Double this to find the area of the whole triangle.
Found answer 2a.\sqrt{x^2-q^2}$. Thanks man you guys so supportive – SSK May 18 '13 at 2:57 With reference to comments: Let's be supportive. If BD is a perpendicular, then you can split ABC into two right-angled triangles, so it is easier to work with: Then you can use the formula$Area = \frac{1}{2}\cdot base \cdot height\$ for each triangle, and add the two. You'll need to find the size of the base of each triangle using the pythagorean theorem.