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I must make 1 addition (x+y=z), 1 subtraction (x-y=z), 1 multiplication (x*y=z), and 1 division (x/y=z) equation with the following numbers. All the numbers must be used to fill x, y, and z of each equation. x, y, and z can consist be 1, 2, or 3-digit numbers.

0-0 available
1-13 available
2-3 available
3-1 available
4-2 available
5-1 available
6-1 avilalble
7-1 available
8-2 available
9-2 available

Thanks!

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Where are you getting these from? –  vadim123 May 17 '13 at 13:40
    
It's from a puzzle. –  GiantDuck May 17 '13 at 13:42
    
I really don't understand your question.First, by "numbers" do you mean digits? Second, you want to use them all up for three different equations? –  Thomas Andrews May 17 '13 at 13:47
    
@ThomasAndrews Yes. What I need is 4 equations as defined above, where all four equations collectively use all the available digits. –  GiantDuck May 17 '13 at 13:51
    
Similar: math.stackexchange.com/questions/393922/… –  vadim123 May 17 '13 at 14:16

1 Answer 1

Finally got it:

1111*1=1111
89/89=1
12+12=24
76-35=41

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