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I must make 1 addition (x+y=z), 1 subtraction (x-y=z), 1 multiplication (x*y=z), and 1 division (x/y=z) equation with the following numbers. All the numbers must be used to fill x, y, and z of each equation. x, y, and z can consist be 1, 2, or 3-digit numbers.

0-4 available
1-9 available
2-1 available
3-2 available
5-1 available
6-1 avilalble
7-0 available
8-1 available
9-1 available

Thanks!

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Perhaps you can edit this question to give some examples as to what e.g. an "addition equation" could look like? And which part of the question are you having trouble with? –  Douglas S. Stones May 16 '13 at 21:22
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@DouglasS.Stones I updated it. Please tell me if it's still not clear. Thanks! –  GiantDuck May 16 '13 at 21:29
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Great! But there's 20 numbers available and these equations use three at a time. That's a problem since 3 does not divide 20. –  Douglas S. Stones May 16 '13 at 21:32
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@DouglasS.Stones I added one more thing: "x, y, and z can consist be 1, 2, or 3-digit numbers." Thanks! –  GiantDuck May 16 '13 at 21:39

1 Answer 1

up vote 1 down vote accepted

There is no magic here, just guess and try. I find $11+18=29, 11-6=5, 100*0=0,31/1=31$ as one of what must be many solutions.

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Works for me. Thank you! –  GiantDuck May 16 '13 at 22:39

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