# What is the time-integral of motion for first order differential equations?

For a second order differential equation (many physical systems) in one variable, I know "procedures" to compute the energy. Given $$q''(t)=f(q(t),q'(t)),\ \ q(0)=q_0,\ \ q'(0)=v_0,$$ if we're lucky we can read off the related Lagrangian $L$, introduce $p=\frac{\partial L}{\partial q}$, do a Legendre transform and we got the Hamiltonian function $H(q,p)$ for which $\frac{\text d}{\text dt}H(q(t),p(t))=0$ for solutions of the differential equation.

We can be more exact and give all the conditions for Noethers theorem to hold and the result is that along the flow $X(t)=\langle q(t),p(t)\rangle$ in phase space given by a solution with initial conditions $X(0)$, the function $H(q,p)$ always takes the same values. It defines surfaces in phase space indexed by initial conditions $X(0)$.

I wonder how to view this for a priori first order systems $$q'(t)=f(q(t)),\ \ q(0)=q_0,$$ where I think this must be even simpler. E.g. I thing some functional $$q(t)\mapsto q(t)-\text{an integral over}\ f(q(t))\ \text{something},$$ should exists which will be constant for solutions of the equation, i.e. only depend on $q_0$. For each $f$, the functional dependence of this "energy" on "$q_0$" will be different.

However, I can't seem to find a general relation. What's the theory behind this, is there an energy'ish time integral of motion? What is the functional dependence on the intial condition, for a suitable constant of motion for for first order systems. And what would be the interpretation, given that we speak of a situation with only one initial condition?

If it is that case that the system is too restricted so that there is no meaningful geometrical interpretation, then let's think about a system of first order differential equations. This is like the one we generated from phase space, except that it doesn't really come from a second order situation and so the intial conditions aren't really e.g. intial position and velocity. I'm pretty sure there are situation where one considers such a directly generated flow (the equation might be more complicated than exponential flow $\dot x\propto x$), but I don't recall any talk about the time-constant of motion in these systems, or how to interpret it.

-

Assuming the first order system is Hamiltonian, for one degree of freedom, we may construct the hamiltonian by integrating the pair of ode's using the relation:

$q'= \frac{\partial H}{\partial p}\qquad p'= -\frac{\partial H}{\partial q}$

Higher order systems have the same "symplectic" structure, and the integrals could have no closed forms. So we would have:

$\frac{\partial H}{\partial p} = f(q),\quad p'=??$

Things seem to get notationally ambiguous. The point is that we must look at variables as conjugated pairs when working in the Hamiltonian formulation of mechanics. As a definitive answer to the OP, if we knew that the system was Hamiltonian, we could in principle integrate the above relations to generate the "Hamiltonian". Also, energy and time are considered to be conjugated in this framework. May I suggest the Poisson bracket as a starting point.

-