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Consider the schema R(ABEFJK) with functional dependencies {BE->JK, J->FA, F->B}.

I was told to find all the keys for this function this is what I did I dont know if im correct

BE->JK
BE -> J  BE -> K
BE->FA BE->F {ABEFJK}
BE is a Key


F->B
FE->BE
FE->JK FE->J FE->K
FE->FA
FE->B
FE is a key

BE->JK
BEF->JKF BEF->JK
BEF->FA BEF->F
BEF->B
BEF is a key
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as per my calculations your answer appears to be fine..BEF is union of other keys so obviously is a key –  Rorschach May 14 '13 at 7:17

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