I am attempting to find the vertical asymptotes, horizontal asymptotes, the local minimum and maximum, and the concavity of the function $f(x) = e^{(2x-x^2)}$
In order to find the vertical asymptotes, it is wherever f(x) is undefined, which I don't believe in anywhere. To find the horizontal asymptotes, I calculate the limit as x tends to infinity. Which is $0$.
I calculated the derivative. That is, $\dfrac{d }{dx}e^{(2x-x^2)} = e^{(2x-x^2)}$(2-2x)
I set it to zero and solve to get the local minimum and maximum.
I take the second derivative.
What does the second derivative tell me about the concavity? How is concavity even expressed in this graph for that matter?