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If I have $12$ tickets in a contest out of $80$ total tickets, and there are $ 6 $ tickets being drawn. What are the odds of me winning something?

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2 Answers

Question 1 How many different ways can we draw $6$ tickets from $80$?

Note that there are $68$ tickets you don't have. Question 2 How many combinations contain only tickets you don't have? What is the probability you don't win?

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Hint: It is easiest to calculate the chance you don't win and subtract from $1$. What is the chance the first ticket drawn doesn't win for you? Given that, how many losing tickets are left? What is the chance the second ticket drawn doesn't win for you? Since all the tickets have to lose, you multiply the probabilities.

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