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How can one get equation 117 on page 21 of the below document by employing Stokes' Theorem to solve the square of the line integral on the left such that the path is closed and infinitesimal, e.g., an infinitesimal rectangle?

http://webusers.physics.illinois.edu/~efradkin/phys582/582-chapter3.pdf

Probably very related to that is how one can get the following identity:

$ S(C) - 1 = \Delta x\Delta y\left [ i\left [ \frac{\partial G_\mu}{\partial \nu} -\frac{\partial G_\nu}{\partial \mu} \right ] - \left [ G_\mu, G_\nu \right ]\right ] $

from the equation below by doing the line integrals also on an infinitesimal rectangle.

$ S(C)({\mathbf R}) = 1 + i\int_{0}^{\mathbf R}G({\mathbf R'})d{\mathbf R'} - \int_{0}^{\mathbf R}\left [ \int_{0}^{\mathbf R'}G({\mathbf R''})d{\mathbf R''}\right ]G({\mathbf R'})d{\mathbf R'} $

The part I cannot get is the one with the commutator. The other parts of the derived equation are fine.

Thanks,

Raphael

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Did you keep in mind that $G$'s are matrices and therefore do not commute? –  Fabian May 5 '11 at 8:53
    
Yes, and it is still unclear to me how the commutator comes from the double integral... –  Raphael R. May 5 '11 at 14:39
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