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Given is the equation:

$$\log_x3+\log_x12 = 2$$

How do I solve it? My idea was to use the formula $\log_a(b) = \frac{\ln b}{\ln a}$ but that does not seem to help here..

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Your idea is fine. Keep running with it. –  Qiaochu Yuan Apr 24 '13 at 1:25
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1 Answer

Hint: $\log_x3 + \log_x12 = \log_x (3 \times 12) = \log_x 36$.

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