This is based on a lesson at Khan Academy that I didn't understand.
In the lesson, the instructor uses the number 512 as an example and the entire prime factorization consists of three groups of three 2s. However, not every number has such a nice prime factorization and I don't understand how to use prime factorization to determine a cube root.
For example, if the number is 1000, I know the cube root is 10, but how do I get there using prime factorization.
The prime factorization of 1000 is 2 * 2 * 2 * 5 * 5 * 5. Since it's six prime numbers, I can't get 3 equal groups of the same number like I could with 512. In another forum someone said to use three groups of the smallest factor, but three 2s doesn't get me 10.
What am I missing?