Given that 3pi/2 < z < 2pi
x = arccos(sin(z))
Given different values for z (which are angles on the unit circle) how would I write the results in these two forms, where C is a constant?:
a.) x = z + C
b.) x = -z + C
Say angle z, = 7pi/4 and z = 5pi/3
I've drawn the unit circle and everything..
For example, when z = 7pi/4, I know x would = arccos(sin(z)).. z = arccos(-sqrt(2)/2)
I also know that cos = (sqrt(2)/2) at 5pi/4 and 3pi/4
But I'm not sure how to represent those in one of the forms given.