I have been thinking of this problem for the post 3-4 hours, I have come up with this problem it is not a home work exercise
Let's say I have 3 coins and I toss them, Here order is not important
so possible sample space should be
0 H, 1 H, 2 HH, 3 HHH (H being heads) TTT, HTT, HHT, HHH
since P(T) and P(H) =1/2;
Here we have fair coins only, Since each and every outcome is equally likely, answer should be
1/4 (is this correct)
and if that is correct, all of the probabilities don't add up to one, will I have to do the manipulation to make it add up to one, or I am doing anything wrong.
EDIT In my opinion, with order being not important, there should be only 4 possible outcomes. All of the answers have ignored that condition.