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The rate of change of the mass $M(t)$ of a tree is approximated by $M'(t)=10t\sqrt{t+15}$ , where the mass is in grams and time $t$ is in days. At time $t =0$, the mass is 150,000 grams. Find the mass of the tree after 10 days. Round constant and final answer to the nearest whole number and include units.

Please show me steps on how to complete the problem. I need to know how to do this for an upcoming exam.

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closed as off-topic by This is much healthier., glace, Deutschland, Paul, Claude Leibovici Jul 1 at 6:02

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Post your attempt please. –  Jerry Apr 16 '13 at 16:51
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1 Answer

You are given an expression for $M'(t)$. To get $M(t)$ you integrate it. So you want $M(t)=150,000+\int_0^t 10t\sqrt{t+15}dt$

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