Probabilistic method problem

100 people are sitting at a round table, they are from 25 countries (4 per country). Pick one from each so that no two are adjacent. Any thoughts?

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Yes. What is the question? – Emre Apr 30 '11 at 3:10
@Emre: Any thoughts on how to do this? – Prbmethod Apr 30 '11 at 3:18
I'd politely ask them to move as appropriate. – Emre Apr 30 '11 at 3:25
@Prbmethod: Please try to frame something that looks like an explicit mathematical question. Here is one, which may not be what you have in mind. There are $100$ people in a room, from $25$ countries, $4$ per country. How many ways are there to seat them at a (large) round table, so that no two people from the same country are next to each other? (And you might want to specify when we should consider two seating arrangements to be the same. If you shift all the people in a good arrangement to the right by $1$ chair, is this the same seating arrangement?) – André Nicolas Apr 30 '11 at 3:56
@Emre: What if they don't move? – AD. Apr 30 '11 at 3:59