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Evaluate the following indefinite integral as a power series:


Help appreciated!

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Where are you running into problems? Is it in the conversion to power series, or is it in the integration of the series? (That changes the question entirely) –  apnorton Apr 8 '13 at 1:48
integrating it as a power series –  user67253 Apr 8 '13 at 1:56
This integral is called dilogarithm –  tetori Apr 8 '13 at 3:00

1 Answer 1

up vote 3 down vote accepted

$$\log{(1-t)} = -\sum_{n=1}^{\infty} \frac{t^n}{n}$$

$$\int dt \frac{\log{(1-t)}}{t} = -\sum_{n=1}^{\infty} \frac{t^n}{n^2}$$

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