Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Evaluate the following indefinite integral as a power series:


Help appreciated!

share|improve this question
Where are you running into problems? Is it in the conversion to power series, or is it in the integration of the series? (That changes the question entirely) –  anorton Apr 8 '13 at 1:48
integrating it as a power series –  user67253 Apr 8 '13 at 1:56
This integral is called dilogarithm –  tetori Apr 8 '13 at 3:00

1 Answer 1

up vote 3 down vote accepted

$$\log{(1-t)} = -\sum_{n=1}^{\infty} \frac{t^n}{n}$$

$$\int dt \frac{\log{(1-t)}}{t} = -\sum_{n=1}^{\infty} \frac{t^n}{n^2}$$

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.