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Basically what I'm looking for is a topological group that is also a non-orientable, n-dimensional manifold

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If you're just considering Lie groups, then they will always be orientable since a Lie group always has a trivial tangent bundle. –  Henry T. Horton Apr 2 '13 at 0:01
    
This seems relevant: math.stackexchange.com/questions/161384/… –  Dominik Apr 2 '13 at 0:08
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You can't do it. Suppose $G$ were an $n$-dimensional manifold which is a topological group. Recall that an orientation of a topological manifold $M$ is a consistent choice of generator for $H_n(M,M\setminus\{x\})\cong \mathbb Z$ for each $x\in M$. But the left-multiplication homeomorphisms $\ell_g\colon G\to G$, $x\mapsto gx$ give canonical isomorphisms from $H_n(G,G\setminus\{e\})$ to $H_n(G,G\setminus\{g\})$.

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