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Let $A$ a ring, for each monomorphism $f:A^m \rightarrow A^n$, I don't know how to prove that $m\leq n$. I can't start the problem, I have no idea, help me please.

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marked as duplicate by rschwieb, Davide Giraudo, Henry T. Horton, Amzoti, Thomas Mar 29 '13 at 17:18

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Duplicate of math.stackexchange.com/q/106786/264 –  Zev Chonoles Mar 29 '13 at 16:37
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Presumably, you mean monomorphisms as $A$-modules? –  Thomas Andrews Mar 29 '13 at 16:37
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If indeed monomorphisms of $A$ modules, are commutative rings intended? There is a noncommutative ring with $R^n\cong R^m$ as right $R$ modules for every pair of positive integers $m,n$. –  rschwieb Mar 29 '13 at 16:41
    
I have a doubt, if f is a monomorphism then f is injective what means that for each element of $A^m$ has an only image in $A^n$, so if I suggest that m>n then some elements of $A^m$ have the same image in $A^n$. It is correct in this exercise? –  rgl4 Apr 7 '13 at 20:46

1 Answer 1

Hint: Exterior power functors preserve monomorphisms of free modules. Use this to get an inequality involving binomial coefficients.

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