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For a pair (A,B) of subsets of the set X={1,2,3,...,100}, let A*B denote the set of all elements of X which belong to exactly one of A or B. What is the number of pairs (A,B) of subsets of X such that A*B={2,4,...,100}?

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The operation "*" is known as the symmetric difference, and usually denoted by $\triangle$. –  Yuval Filmus Apr 20 '11 at 6:52
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3 Answers 3

up vote 4 down vote accepted

Hint: What can you say about each element in $A\triangle B$? What can you say about each element not in $A\triangle B$?

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Yes, it's just a difference in notation, but how to count? I never came across this sort of operation earlier. –  Bhaskar Dey Apr 20 '11 at 6:59
    
There is no involved counting necessary here. The essential point is to s e e what kind of pairs $A$, $B$ are possible under the given constraint. –  Christian Blatter Apr 20 '11 at 8:08
    
I think we're being too subtle. Five hours, and no one (but me) has upvoted your answer, and no one at all has upvoted mine. –  Gerry Myerson Apr 20 '11 at 13:09
    
@Bhaskar: to follow up on Yuval and Gerry-If $1 \in A$, is $1 \in B$? If $2 \in A$, is $2 \in B$? –  Ross Millikan Apr 20 '11 at 13:51
    
@Gerry Five hours does not seem much. And I like waaaay more your hints and Yuval's and Ross's than the flat answers given to obvious homework questions too often on this site. –  Did Apr 21 '11 at 7:58
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Different hint: given $A$, how many different possibilities are there for $B$?

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I like your hint better. –  Yuval Filmus Apr 20 '11 at 15:45
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Yet another hint: show that the set of all subsets of $X$ forms a group under symmetric difference, then note that you're asking how many times a given group element shows up in the group table.

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