I know a little bit about probability but I am not sure how to calculate this:
In a dice game of blackjack, there are two parties. The player and the dealer. The aim of this game is to get as close to $21$ without going over, using six sided dice which has an equal chance of landing on each side. Both parties may use as many dice as they like. If the player goes over 21 then they lose and similarly to casino blackjack, the player's turn is first. For the purpose of this question, assume that the player will always keep (stay) the value of either 19, 20, 21 and would continue if the value is 18 or under. If there is a draw then the game is repeated and there is no winner.
Thanks in advance and I hope this is enough information to draw a reasonable answer.