# Speed of Light and distances [closed]

that if for some reason, the speed of light is $c =300,000 Km/s$, they say the distance to any other galaxy is let's say

 50 light years


Supossing we can travel at a speed of:
$c^2$, $c^3$, $c^4$ and $c^5$..

How is this time reduced when traveling at this speed (50 light years)?

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Might be better suited as a (silly) question in the physics SE. –  Carl Brannen Apr 15 '11 at 22:37
$c^2, c^3, c^4, c^5$ are not velocities. –  Qiaochu Yuan Apr 15 '11 at 23:02
Nothing can go at the speed of light, except light itself. And nothing can go over it. According to Einstein, anyways, and he always was a bit weird. :) –  muntoo Apr 16 '11 at 2:29
Well, I was asking, and supossing, we do not really know if there is something that could travel faster than light –  cMinor Apr 16 '11 at 3:26

## closed as off topic by Ross Millikan, Rasmus, Pete L. Clark, Qiaochu YuanApr 15 '11 at 23:02

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Remember that distance = rate * time. A light year, despite the "year" in the name, is a unit of distance, the distance light can travel in one year, about 9.47 E12 km= 300,000 km/s * 3155760 s/yr * 1 yr. Traveling at c^2 makes no sense as the units are now km^2/s^2.

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But supossing, there is a way to travel at this speed?, How is the time it takes to get to some place? –  cMinor Apr 15 '11 at 22:00
If you are asking (contrary to reltivity) the time reduction from traveling at 300,000^2 km/sec relative to traveling at 300,000 km/sec, it is a factor 300,000. But if you use cm/sec, the speed of light is 3 E10 cm/sec, the square would be 9 E 20, the the reduction is a factor 3 E10. –  Ross Millikan Apr 15 '11 at 22:03