# How to prove that every algebraically-closed integral domain is a field?

I'm trying to come up with some good idea on how to prove this, but I can't figure it out. But I suppose it can be done rather easy.=/

Suppose R is an integral domain and that R is algebraically closed. Prove that it then follows R is a field.

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Let $a$ be a non-zero element of your ring $R$. Then the polynomial $ax-1$ has a root in $R$... –  Mariano Suárez-Alvarez Apr 15 '11 at 1:50
@Mariano: Do we need to use the fact that there are no zero divisors? –  Yuval Filmus Apr 15 '11 at 1:54
If for every $a\in R\setminus 0$ the polynomial there exists a $b\in R$ such that $ab=1$, then there are no divisors of zero. (I am assuming the ring is commutative...) –  Mariano Suárez-Alvarez Apr 15 '11 at 2:07