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I am attempting to find a 'smarter' way to solve a matrix, in the form $Ax=B$, where



where $N$ is constant, $K$ is a constant matrix, and $F$ is a vector of;


where $Y$ is a vector constant.

I'm not hugely mathematical, and my linear algebra skills could be put on the back of a napkin, but seeing this kind of repetition indicates to me that there must be a shortcut for this.

Does anyone have any insights?

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You can cancel the $F_i$'s. –  Yuval Filmus Apr 15 '11 at 1:20
I was thinking more about the structure of the resultant matrix but yeah, I wanted a second opinion on that too (I have no real understanding of the weirdnesses of linalg...) –  Andrew Bolster Apr 15 '11 at 1:23
Think of it as a system of equations. For each $i$ you have an equation of the form $\sum_j A_{ij} x_i = B_i$. In your case, this is $\sum_j -F_i/K_{ji} = NF_i$, so you can cancel the $F_i$'s. Otherwise it's almost completely arbitrary (other than the fact that $-1/K_{ji}$ cannot be zero). –  Yuval Filmus Apr 15 '11 at 1:44
You can also cancel the $N$ if you want. Solve if for RHS which is constant $1$, then multiply the result by $N$. –  Yuval Filmus Apr 15 '11 at 1:45
There's a typo above; it should read $\sum_j A_{ij} x_j = B_i$. –  joriki Apr 15 '11 at 7:50

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