# Using the Cauchy integral formula to evaluate $\int_{\gamma=(a,a)} \frac{z}{z^4-1} dz$.

I'm trying to understand how to use the Cauchy integral formula, but a bit confused as to how to use it as I cant seem to get the right answer!

$$\int_{\gamma=(a,a)} \frac{z}{z^4-1} dz$$ where $a\in\mathbb{R}$ and $a>0$ and $a\not= 1/2$.

please note: this must be solved using cauchy integral formula!

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 shouldn't $a=1$ make much more problems? what you mean by gammer=(a,a)? – Dominic Michaelis Mar 14 at 19:04 what is gammer=(a,a)? – Shu Xiao Li Mar 14 at 19:06 Not sure, i have just found a question that i dont understand, i didnt make it up! Next to the integral sign, there is a gammer(a,a) – sarah Mar 14 at 19:09 i think it means w=a and r=a? – sarah Mar 14 at 19:10 @sarah I assume that by gammer you mean $\gamma$? – Alexander Gruber♦ Mar 14 at 19:16
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