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A builder spent £4,950 in buying some property, in renovating it and equipping it for use.If the cost of renovation was 1/10 of the cost of buying, and if the equipment cost 1/8 of the price of these two combined, what did he pay for the property in the first place?

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closed as off-topic by 900 sit-ups a day, Babak S., PVAL, rogerl, Ian Mateus Aug 3 at 22:07

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1 Answer 1


Let $x$ be the buying cost.

$\frac{1}{10} \cdot x$ will be renovating cost.

Finally, for equipping $=\frac{1}{8} \cdot (\frac{1}{10}\cdot x+x)$

Now add 'em all and equate it to 4,950. You get $x$.

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