Why this:
$(3 \ast (3^{k-1} + 1) - 2)$
equals to:
$(3 \ast 3^{k-1} + 3 - 2)$
and why/how from this we get to this:
$(3^k + 1)$
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Because $a*(b+c)=a*b+a*c$ and $x^m*x^n=x^{m+n}$ |
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