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I have this confusion about the time complexity of least squares problem. Suppose

minimize $||Ax-b||^2$

Analytical solution = $x^* = (A^TA)^{-1}A^Tb$

computational time proportional to $n^2k$, $A \in \mathbb{R}^{k\times n}$

I didn't get how the computation time is $n^2k$

Here is the source http://classes.soe.ucsc.edu/cmps290c/Spring05/lectures/intro.pdf

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$\epsilon$ (\epsilon) is a variable name whereas your $A$ is in the set $\mathbb{R}^{kn}$. So you should use $\in$ (\in). –  xavierm02 Mar 8 '13 at 12:19
    
Also to get $\mathbb{R}$, you can use \mathbb{R}. And I think you should simply use $kn$ instead of $kxn$ but if you really want the multiplication operator to appear, use $\times$ (\times). –  xavierm02 Mar 8 '13 at 12:21
    
In fact you should keep the $\times$ because otherwise, we wouldn't be able to interpret it as a matrix. –  xavierm02 Mar 8 '13 at 12:25
    
check out this link for the reasoning of $n^2k$... math.stackexchange.com/questions/84495/… –  Learner Mar 8 '13 at 13:00
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