In the triangle ABC, the height of AH is $11$ cm, and the length of the rib BC is $17$ cm. The angle inbetween the rib AB to height AH is $25^\circ$.
A) Please write an trigonometric expression that expresses the ratio between HB and AH. Done, it is $tan(25)=BH/AH$
B) Calculate the length of BH. Answer: $5.13$ cm.
C) Calculate the size of the angle CAH. <- Im having problems with this one. How ever I found the size of CH, and added BH to it, . but Idk how i would find CA , because A is a X (On the left triangle) thats the issue.