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the question is:

x dy/dx= 2y ; y(0)=0

because when i solve this problem the integration constant 'c' gets zero... and i have to find its value in order to calculate a solution to given IVP

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@ Sadia: Are you sure this question is stated correctly. Because the ODE yields a solution of zero. – night owl Jul 4 '11 at 12:14

Solving this problem, I get \begin{equation} y = ax^2 \end{equation} with $a$ a constant. Could you use this constant to find a solution for your IVP ?


I don't think this differential equation has a unique solution, if you check you see that \begin{equation} f(x,y) = \frac{2y}{x} \end{equation} is not continuous in $(0,0)$, so Picard's Theorem doesn't hold.

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i didn't get your point! please elaborate furthur... – sadia abid Apr 9 '11 at 8:31
sorry I forgot to enter side condition, I have edited my question please see it now... – sadia abid Apr 9 '11 at 8:38

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