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Use the trigonometric identities to find $\sin x$, $\tan x,$ and $\cot (-x)$, given $\cos x = 3/5$ and $x$ in quadrant IV.

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To get more relevant answers (and less downvotes), try explaining what you have already tried and what your doubts are. – Wheepy Mar 2 at 15:51

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Hint: Make use of $\sin^2x+\cos^2x=1$, $\tan x=\frac{\sin x}{\cos x}$, $\cot x = \frac{\cos x}{\sin x}$, $\cot(-x)=-\cot x$. You need the quadrant to determine the sign of $\sin x$.

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Using All Sin Tan Cos formula, $\tan x<0$ and $\sin x<0$ as $x$ lies in the Fourth Quadrant.

Now, $\sec x=\frac1{\cos x}=\frac53$

$$\text{ So, }\tan x=-\sqrt{\sec^2x-1}$$

$$\sin x=\cos x\cdot\tan x\text{ or } =-\sqrt{1-\cos^2x}$$

$$\cot(-x)=-\cot x=-\frac1{\tan x}$$

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