I want to prove that $(\mathbb{N},\tau)$ is a topological space, where $\tau=\{ \mathbb N,\emptyset\}\cup\{\{1,\dots,n\}:n\in \mathbb{N}\}$.
I need a hint to prove that an arbitrary union of elements of $\tau$ is in $\tau$.
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I want to prove that $(\mathbb{N},\tau)$ is a topological space, where $\tau=\{ \mathbb N,\emptyset\}\cup\{\{1,\dots,n\}:n\in \mathbb{N}\}$. I need a hint to prove that an arbitrary union of elements of $\tau$ is in $\tau$. |
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Your hint is: consider the maximum number in the family over which you are taking the union. |
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Let $\{U_i: i\in I\}$ be an indexed family of elements of $\tau$. Then $\bigcup_{i\in I}{U_i}=\mathbb N$, or $\bigcup_{i\in I}{U_i}=\emptyset$, or $\bigcup_{i\in I}{U_i}=U_k$ for some $k\in I$ such that $\max{U_k}\ge \max{U_j}$ for all $j\neq k$. In all cases, the union is in $\tau$. Is this correct? |
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