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There are two functions , for example $f(n)=3\sqrt{n}$, and $g(n)=\log n$. Which one dominates, in other words, is $f(n)=O(g(n))$ or $f(n)= \Omega(g(n))$?

Thank you.

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$f(n)$ grows much faster than $g(n)$. –  André Nicolas Feb 25 '13 at 7:55

2 Answers 2

$f$ dominates. The logarithm function as $+\infty$ gets smaller than any power function.

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$f$ can also be written as $f = 3\cdot n^{\frac{1}{2}}$, which is an exponential function in $n$, and hence it grows faster than $g$ (which is logarithmic).

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