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In the figure above, the circle with center $O$ is inscribed in square $ABCD$. What is the area of the shaded portion of the circle?

(A) $\pi/4$

(B) $\pi/2$

(C) $\pi$

(D) $3\pi/2$

(E) $2\pi$

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What have you tried? –  Chris Eagle Feb 24 '13 at 18:22

2 Answers 2

up vote 3 down vote accepted

Hint:
Radius of the circle is ...
Area of the whole disc is equal ...
What part of the disc is shaded?
Therefore, area of the shaded part is equal ...

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So it is π1^2 A=3.14 then 3.14(1/4)= .785 Thus π/4 –  Little Jon Feb 24 '13 at 18:34

Hint: The circle has radius $1$. By symmetry (join the centre of the circle to the other corners of the square) the shaded part of the circle is one-quarter of the whole circle.

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