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I have this double sum

$\displaystyle\sum_{k=1}^{N}\sum_{b=2}^{L} \varphi(b)(b^{2}2^{k})$

I wish to reduce this to a single-sum function (by simplifying/getting rid of the inner summation loop so I only loop from 1 to N). Can it be done?

$\varphi(b)$ is the totient function

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If I read the formula correctly, it is the outer sum that is easiest to get rid of. –  André Nicolas Feb 23 '13 at 7:08
@AndréNicolas L = floor(N/k) if that matters –  NullOverNull Feb 23 '13 at 7:14
From the notation you used, I thought $L$ was unrestricted, hence my comment. –  André Nicolas Feb 23 '13 at 7:29

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