Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I have already introduced myself as the communications liaison of a small study group of math Ph. D.'s who are thirty plus years away from grad studies. We are currently working on Stewart & Tall's ANT and Fermat's Last Theorem. We are having as rough time with Chapter 5 and are seeking alternative readings. Unfortunately there seem to be as many approaches to ANT as there are textbooks written. This makes it much harder to find those "alternate Readings" which follow their (Stewart & Tall) development. Any direction would be appreciated.

share|improve this question
    
I think this question is more of algebraic number theory than of number theory. You could consider retagging it. Thanks. –  awllower Feb 22 '13 at 3:15

2 Answers 2

I wrote up some notes on Algebraic Number Theory. I was following Stewart & Tall but also a couple of other books. See if you find anything useful there.

share|improve this answer
    
if I haven't thanked you already, let me do it now. If you continue to develop these notes and solutions I would be very, very happy if you would email them to me. –  DaveUM Feb 27 '13 at 0:56
    
Dave, I doubt that I'll get back to this until the next time I teach the course, and that might be next year, or it might be never. But if you can find my email address and drop me a line, I'll try to put it somewhere where it will remind me of your request. –  Gerry Myerson Feb 27 '13 at 2:37

Some of my favorites:
Simple and direct method By Janusz
One of my favorite authors by Jürgen Neukirch
Available online notes J.S.Milne
A classic Hecke
If you know some background in the integration on groups, then this is a classic! André Weil
I know not your book, so I cannot say if they follow the approaches in your book, but I am sure that the number of approaches to ANT is not too large, so that they are essentially equivalent.(Per chance they look different at first glance, but they might turn out to be equivalent in the end.)
Hope this helps.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.