Let $X$ and $Y$ be schemes of finite type over a field $k$. Assume that $X$ is geometrically reduced. If two morphisms $f,g$ from $X$ to $Y$ agree as maps on $X(\bar{k}) \rightarrow Y(\bar{k})$ , I want to show that they are the same maps topologically. Here $\bar{k}$ denotes the algebraic closure. I can see they agree on closed points, but why do they agree on other points?
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If $Y$ is a separated scheme, then the subset $K\subset X$ of points where $f$ and $g$ agree is closed in $X$. Note that density (and even very density) of $X^{cl}$ is a general property of schemes locally of finite type over a field:cf. EGA IV, Troisième Partie, §10. |
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