What is the probability of a 4-digit number of the form abcd(a,b,c,d are all different) is a multiple of 11?
(a) 0.1420 (b) 0.0480 (c) 0.0720 (d) 0.091
Can it be assumed that the ratio of 4-digit numbers of the form abcd which are multiples of 11 to that of all 4-digit numbers of the form abcd is 1? If yes, then is this right?
(((9999-1001)/11) + 1) / ( 9999 - 999 )= 91/1000
EDIT: This is what I intend to know
Is the proportion of the "all digits distinct" 4-digit numbers that are divisible by 11 among all 4-digit numbers divisible by 11 equal to the proportion "all digits distinct" 4-digit numbers among all numbers from 1001 to 9999?
Thanks to Andre Nicolas for stating this in his comment