Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

How do you find the point for a circle and find the radiums when x squared has a co-efficient?

share|improve this question
1  
I'm assuming you mean the point which is the center of the circle? Could you give an example of what you mean? What equation are you working with, e.g.? –  amWhy Feb 19 '13 at 14:25
    
you can divide the whole equation by the coefficient of $x^2$ and then treat it the way you do any of your "normal" equations. –  Maesumi Feb 19 '13 at 14:29
add comment

1 Answer 1

For an equation of the form $$ax^2 + by^2 = c^2$$ unless $a = b$, you do not have a circle, but rather, an ellipse.

If $a = b$, then you do have a circle, and you can rewrite your equation as $$x^2 + y^2 = \left(\frac ca\right)^2\tag{1}$$

In this case $(1)$, the center of the circle is the origin, and the radius is $\dfrac ca$.

In general, the equation of a circle with center $(x_0, y_0)$ and radius $r$ is given by:$$(x- x_0)^2 + (y-y_0)^2 = r^2$$

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.