The question here: A number when successively divided by 9, 11 and 13 ... I found the answer to it in a book and this was the answer:
The least number that satisfies the condition= 8 + (9×9) + (8×9×11) = 8 + 81 + 792 = 881
I brute forced the solution like this when I didn't get the author's solution.
N = 9a+8.
And we have
a = 11b+9, and
b=13c+8 (Successively it's said in the question, no?)
So N = 99b+89 = 99(13c+8)+89 = 1287c+792+89 = 1287c+881.
So lowest value of N = 881 (c = 0)
I know I'm probably missing something really easy here, I'm not understanding the author's calculations.