Let $M$ and $N$ be $R$-modules. Suppose we complete them with respect to an ideal $\frak{m}$ of $R$. If we have $$M^\wedge_\mathfrak{m} \simeq N^\wedge_\mathfrak{m}$$must if be the case that $M \simeq N$?
It would appear, from something I am reading, that the answer is no. If so, is there a simple counter example? (You can assume $R$ is nice, e.g. Noetherian, local).