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I am attempting to prove the following:

If $g:X \to S^n$, $n \ge 1$, is a continuous map whose image $g(X)$ is a proper subset of $S^n$, then $g$ is null-homotopic.

Just before this I proved that if $Y$ is contractible, then every continuous map $f:X \to Y$ is null-homotopic. Therefore I'd like to show that any proper subset of $S^n$ is contractible. What is the best way to do this? I wanted to use that $S^n$ is an $n$-manifold to associate it with an open set in $\mathbb{R}^n$, which, if it is convex, is contractible. However, I don't think this works, and it seems like overkill anyway.

What is the best way to show that a proper subset of $S^n$ is contractible?

Thanks.

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It is not true that any proper subset of $S^n$ is contractible!! What is true is that $S^n - x$ for any point $x$ is contractible, and that is enough. –  Dylan Wilson Feb 13 '13 at 2:28
    
@Dylan: Of course, I should have realized that... Thanks. –  Alex Petzke Feb 13 '13 at 2:32

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