Given Data :
Normal Distribution function
$$P(x \leq -1) = P(y \geq 2)$$
x : mean= 1 variance= 4
y : mean= -1 variance= to be found..?.
Ans: 9
How to solve..?
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Given Data : Normal Distribution function $$P(x \leq -1) = P(y \geq 2)$$ x : mean= 1 variance= 4 y : mean= -1 variance= to be found..?. Ans: 9 How to solve..? |
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Firstly, $P(x\le-1)=\Phi\left(\frac{-1-1}{\sqrt4}\right)=\Phi(-1)$ Also, $P(y\ge2)=P(y\le-4)=\Phi\left(\frac{-4-(-1)}{\sigma}\right)=\Phi\left(\frac{-3}{\sigma}\right)$. So we have $\frac{-3}{\sigma}=-1$ and $\sigma^2=9$. |
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