# Find magnitude and direction of resultant of three given forces?

Using this diagram:

A hot-air balloon is ready for take-off. The diagram shows the balloon, tethered by two ropes AB and CD, reach attached to the balloon and the horizontal ground. The weight of the balloon is 3000N. The tensions in AB and CD are 250N and 100N respectively. AB and CD make angels of $60°$ and $30°$ respectively with the vertical.

(i) By modelling the balloon as a particle, find the magnitude and direction of the resultant of the three given forces on the balloon.

Can anyone please point me in the correct direction?

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rx=86.60 ry=50 ${}{}{}{}{}{}{}{}{}{}{}$ –  user85226 Jul 6 '13 at 13:05

$$F_{down} =100 cos(30)$$ $$F_{left} =100 sin(30)$$