# Is there a natural topology on C(X), if X is infinite-dimensional?

Suppose $X$ is an infinite-dimensional Banach space.

Is there a natural topology on $$C(X)=\{f:X\to\mathbb{R}: \text{ f is continuous}\}?$$

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@NateEldredge Oops, I did not read the first line... – 1015 Feb 2 '13 at 18:33
@NateEldredge, exactly. It is not clear what would be a family of seminorms that gives $C(X)$ a Frechet space topology. – Cantor Feb 2 '13 at 18:33
@Cantor Sorry, my comment was absolutely pointless, I had not read the question carefully. – 1015 Feb 2 '13 at 18:36

So, what is one natural weak topology on $C(X)$?! – Cantor Feb 2 '13 at 18:35
@Cantor: Sorry, meant to say the weak* topology. It's the weak topology with respect to the functions $\{\phi\mapsto \phi(x) \ | \ x \in X\}$. – Jim Feb 2 '13 at 18:41
Well, the weak* topology is a weak topology. It's just that if you say weak topology that's a topology you put on a space using a set of functions on that space. We have a space and a set of functions but we don't want a topology on $X$, we want a topology on $C(X)$, so it's a little confusing to just say weak topology. If we want the topology to be on $C(X)$ we have to specify the functions on $C(X)$ that we are taking the weak topology with respect to. By saying weak* topology I'm just being specific about what those functions are. – Jim Feb 2 '13 at 18:56