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Using Clayton's answer, and because Valentine's Day is just a couple of weeks away, it seemed appropriate to post this image of the octagon:
Hint: An octagon has $1080^\circ$, and you have the equation $$2\theta+\theta+\cdots+\theta=9\theta=1080^\circ.$$
The sum of the interior angles of an octagon is $1080^\circ$.
There are eight interior angles, one twice the measures of all others:
Now solve for $\theta$ (which is the measure of the 7 equal angles),
and then compute $2\theta$, the measure of the angle that is twice the size of the other 7 interior angles.