Solve a first order differential equation by substitution

For a given differential equation $$xy'+2y\log y -4x^2y = 0;$$ $$y(1)=1$$

I want to use the substitution $v=\log y$. Which implies that $$v'=\frac{dv}{dy}\frac{dy}{dx}= \frac{1}{y} y'$$Hence: $$y'=yv'$$

That being said, solving the equation I try as follows:

$$xyv'+2yv-4x^2y = 0$$ $$xv'+2v = 4x^2$$ $$v'+\frac{2}{x}v= 4x$$ $$v'=4x-\frac{2}{x}v$$

How can I use seperation of variables here? Or how can I solve this thing ?

thanks

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It is a liner equation, you do not separate the variables. – Artem Jan 26 '13 at 13:33

You've reduced your equation to the so called Bernoulli differential equation. Using notation from wikipedia just set $$P(x)=\frac{2}{x}\qquad Q(x)=4x\qquad n=0$$
@Norbert Why not Riccati equation with $q_2(x)=0$? – Artem Jan 26 '13 at 13:45