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How to solve this? because now I am going to have an exam and I dont know how to solve this

$$ \lim_{x\to 0} {\sqrt{1-4x^2}\over x^2}$$

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Is it undefine? – Kns Jan 25 '13 at 9:36
Hmm... I guess the question should be $\lim\limits_{x\to 0}\dfrac{\sqrt{1-4x^2}-1}{x^2}$ – Shane Chern Jan 25 '13 at 11:14
up vote 2 down vote accepted

What is your problem? You have $$\lim_{x\to0} \sqrt{1-4\,x^2} = 1$$ and $$\lim_{x\to0} x^2 = 0.$$ Now, you should conclude what your limit is.

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