^ That's the problem, but I'd also like to know why...
I have:
a. True
b. True
c. False, because you'd need to have a set with the null set in it on the right hand side.
d. True, seems like what was missing from c
e. True
f. True
g. True
Thanks!
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^ That's the problem, but I'd also like to know why... I have: a. True b. True c. False, because you'd need to have a set with the null set in it on the right hand side. d. True, seems like what was missing from c e. True f. True g. True Thanks! |
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Hint:
So, for example $a$ and $b$ are true because you can easily find the element $\emptyset$ in both $\{\emptyset\},\{\emptyset,\{\emptyset\}\}$. While $c$ is wrong, since $\{\emptyset\}$ is not an element of itself.
So, for example, $f$ is correct. Because in it we see that $\{\emptyset\}\in\{\emptyset,\{\emptyset\}\}$ and so we have $$\{\{\emptyset\}\}\subset\{\emptyset,\{\emptyset\}\}$$ |
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