# expression for the sum involving digamma function

I got this answer from WolframAlpha. Does anyone know how even to approach it to obtain the solution using digamma function. Please don't solve it, just show me in the right direction!

$$\sum_{k=1}^n \frac1{(n^2-4 (k-1)^2)} = \frac{\pi n \cot(\pi n/2)-n \psi^{(0)}(n/2)+n \psi^{(0)}(3 n/2)+2}{4 n^2}$$

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